Abstract
It is known that any square matrix A of size n over a field of prime characteristic p that has rank less than n/(p - 1) has a permanent that is zero. We give a new proof involving the invariant X p . There are always matrices of any larger rank with non-zero permanents. It is shown that when the rank of A is exactly n/(p - 1), its permanent may be factorized into two functions involving X p .
Original language | English |
---|---|
Pages (from-to) | 175-177 |
Number of pages | 3 |
Journal | Designs Codes and Cryptography |
Volume | 62 |
Issue number | 2 |
DOIs | |
Publication status | Published - Feb 2012 |
Keywords
- Matrix
- Permanent
- Prime characteristic
- Rank