It is known that any square matrix A of size n over a field of prime characteristic p that has rank less than n/(p - 1) has a permanent that is zero. We give a new proof involving the invariant X p . There are always matrices of any larger rank with non-zero permanents. It is shown that when the rank of A is exactly n/(p - 1), its permanent may be factorized into two functions involving X p .
|Number of pages||3|
|Journal||Designs Codes and Cryptography|
|Publication status||Published - Feb 2012|
- Prime characteristic